(20 points) A random sample of =1200 n = 1200 registered voters and found that 620 would vote for the Republican candidate in a state senate race. Let p represent the proportion of registered voters who would vote for the Republican candidate. Consider testing 0:=.50 H 0 : p = .50 :>.50 H a : p > .50 (a) The test statistic is z =

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Answer:

The test statistic is Z = 1.157

Step-by-step explanation:

Given that:

The sample size n = 1200

The sample proportion of those that will vote for the Republican candidate is represented by [tex]\hat p = \dfrac{x}{n}[/tex]

[tex]\hat p = \dfrac{620}{1200}[/tex]

[tex]\hat p =0.5167[/tex]

The null and the alternative hypothesis can be computed as:

[tex]H_o: P=0.50 \\ \\ H_a :P>0.50[/tex]

The formula for the one-sample Z-test for the population proportion can be expressed as:

[tex]Z = \dfrac{\hat p - P_o}{\sqrt{\dfrac{P_o(1-P_o)}{n}}}[/tex]

[tex]Z = \dfrac{0.5167 - 0.5}{\sqrt{\dfrac{0.5(1-0.5)}{1200}}}[/tex]

[tex]Z = \dfrac{0.0167}{\sqrt{\dfrac{0.5(0.5)}{1200}}}[/tex]

[tex]Z = \dfrac{0.0167}{\sqrt{\dfrac{0.25}{1200}}}[/tex]

[tex]Z = \dfrac{0.0167}{\sqrt{2.08333333\times10^{-4}}}[/tex]

Z = 1.157

Testing the hypothesis, from the information given, it is found that the test statistic is z = 1.157.

The null hypothesis is:

[tex]H_0: p = 0.5[/tex]

The alternative hypothesis is:

[tex]H_1: p > 0.5[/tex]

The test statistic is given by:

[tex]z = \frac{\overline{p} - p}{\sqrt{\frac{p(1-p)}{n}}}[/tex]

In which:

  • [tex]\overline{p}[/tex] is the sample proportion.
  • p is the proportion tested at the null hypothesis.
  • n is the sample size.

For this problem, the parameters are: [tex]p = 0.5, n = 1200, \overline{p} = \frac{620}{1200} = 0.5167[/tex]

Hence, the value of the test statistic is:

[tex]z = \frac{\overline{p} - p}{\sqrt{\frac{p(1-p)}{n}}}[/tex]

[tex]z = \frac{0.5167 - 0.5}{\sqrt{\frac{0.5(0.5)}{1200}}}[/tex]

[tex]z = 1.157[/tex]

The test statistic is z = 1.157.

A similar problem is given at https://brainly.com/question/24166849