Answer:
C. 825 ft³
Step-by-step explanation:
Height of the hole = 42 ft
Radius of the hole = ½*diameter = ½*5 = 2.5 ft
How large the hole is = the volume of the cylindrical hole
Volume = [tex] \pi r^2h [/tex]
Plug in the values
[tex] Volume = \pi *2.5^2*42 = 824.67 [/tex]
The hole is approximately 825 ft³ large (nearest whole number).
