Answer:
[tex]a=0.125\ m/s^2[/tex]
Explanation:
Given that,
Mass of Efua, m = 40 kg
Force, F = 5 N
We need to find Efua's resulting acceleration. We know that the force acting on an object is given by :
F = ma
where a is acceleration
[tex]a=\dfrac{F}{m}\\\\a=\dfrac{5\ N}{40\ kg}\\\\a=0.125\ m/s^2[/tex]
So, the resulting acceleration is [tex]0.125\ m/s^2[/tex].
