Answer:
The height of the cliff is 28.57 m.
Explanation:
Given;
initial velocity of the rock, u = 12.6 m/s
time of motion, t = 1.45 s
The height of the cliff is given by;
h = ut + ¹/₂gt²
h = (12.6 x 1.45) + ¹/₂(9.8)(1.45)²
h = 18.27 + 10.30
h = 28.57 m
Therefore, the height of the cliff is 28.57 m.
