Answer:
[tex]I=0.12\ kg-m^2[/tex]
Explanation:
Given that,
Mass of a thin rod, m = 1 kg
Length of the rod, l = 0.6 m
We need to find the rotational inertia of the rod if it rotates about one of its ends. It can be given by the formula as follows :
[tex]I=\dfrac{1}{3}ML^2\\\\I=\dfrac{1}{3}\times 1\times (0.6)^2\\\\=0.12\ kg-m^2[/tex]
So, the moment of inertia of the rod about one of its ends is [tex]0.12\ kg-m^2[/tex].
