9514 1404 393
Answer:
x = (-3±√69)/10
Step-by-step explanation:
Perhaps you want to find the solutions using the quadratic formula.
For the equation ...
ax² +bx +c = 0
The solution is given by the formula ...
[tex]x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]
Here, we have a=5, b=3, c=-3, so the values of x are ...
[tex]x=\dfrac{-3\pm\sqrt{3^3-4(5)(-3)}}{2(5)}\\\\\boxed{x=\dfrac{-3\pm\sqrt{69}}{10}}[/tex]
