Answer:
I = 1.944 A
Explanation:
Given the following data;
Charge, Q = 3.5C
Time, t = 1.8 secs
Charge of a substance is given by the formula;
[tex] Q = It[/tex]
Where;
Q is the amount of charge measured in Colombs.
I is the current measured in Amperes.
t is the time measured in seconds.
Making I the subject of formula, we have
[tex] I = \frac {Q}{t} [/tex]
[tex] I = \frac {3.5}{1.8} [/tex]
I = 1.944 A
Therefore, the current in the circuit is 1.944 Amperes.
