bonolokoena5 bonolokoena5

17-11-2020
Mathematics

contestada

how to factorise 8a3-b3

Respuesta :

lisee787 lisee787

17-11-2020

Answer:

Step-by-step explanation:

Ver imagen lisee787

Answer Link

jimrgrant1 jimrgrant1

17-11-2020

Answer:

(2a - b)(4a² + 2ab + b²)

Step-by-step explanation:

8a³ - b³ ← is a difference of cubes and factors in general as

a³ - b³ = (a - b)(a² + ab + b²) , thus

8a³ - b³

= (2a)³ - b³

= (2a - b)((2a)² + 2ab + b² ), that is

(2a - b)(4a² + 2ab + b²)

Answer Link

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