Answer:
[tex]\frac{2x}{3y}[/tex]
please give me brainliest!
Step-by-step explanation:
[tex]\frac{\sqrt{4x^2}}{3y} = \frac{2x}{3y}[/tex]
I'm assuming that the entire 4x^2 term is under the radical sign. If it isn't, then
[tex]\frac{\sqrt{4}x^2}{3y} = \frac{2x^2}{3y}[/tex]
