Answer:
The correct answer is 0.11 L
Explanation:
From the problem, we have the following data:
moles CaCl₂= 0.039 mol
molarity = 0.340 M = 0.340 mol CaCl₂/L
According to this, the solution has 0.340 mol of CaCl₂ in 1 L. If the total number of moles is 0.0369, we can find the volume as follows:
V= moles/molarity = 0.0369 mol x 1 L/0.340 mol = 0.108 L ≅ 0.11 L
