Answer:
[tex](3^m)^n=1[/tex]
Step-by-step explanation:
[tex](m+n)^2=m^2+n^2\\m^2+2mn+n^2=m^2+n^2\\(m^2+n^2)-(m^2+n^2)+2mn=0\\2mn=0\\This\ equation\ has\ two\ solutions\ : m=0,n=0\\\\But\ either\ way\ will\ result\ in\ the\ same\ answer.\\If\ m=0\ then,\\(3^0)^n\\=1^n\\=1\\\\If\ n=0 \ then,\\(3^m)^0\\=1[/tex]
