Answer:
1st integer=x
2nd integer=x+1
3rd integer=x+2
4th integer=x+3
2(x +(x+2))= 3(x+1) +11
solve
2 (2x +2) = 3x + 3 + 11
4x + 4 = 3x + 14
-3x-4 =-3x -4
x=10
1st integer=10
2nd integer=11
3rd integer=12
4th integer=13
Step-by-step explanation:
hopefully this helped
