Respuesta :

konrad509
[tex]D:x>0\\ \log x+\log x^2+\log x^3=-6\\ \log (x\cdot x^2\cdot x^3)=\log 10^{-6}\\ x^6=10^{-6}\\ x^6=\left(\frac{1}{10}\right)^6\\ \boxed{x=\frac{1}{10}}[/tex]
FirstSineOfMadness
Log x^n = nLog x
log x + log x^2 + log x^3
Log x + 2 log x +3 log x = -6
6 log x = -6
Log x = -1
X=10^-1 = 1/10
Respuesta final
X=1/10

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