angidella22 angidella22
  • 20-10-2020
  • Mathematics
contestada

F(x)=-(2x-1)^2-2. What is the value of f(-3)

Respuesta :

jimthompson5910 jimthompson5910
  • 20-10-2020

Answer:  -51

Work Shown:

f(x) = -(2x-1)^2 - 2

f(-3) = -(2*(-3)-1)^2 - 2 ... replace every x with -3

f(-3) = -(-6-1)^2 - 2

f(-3) = -(-7)^2 - 2

f(-3) = -49 - 2

f(-3) = -51

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