Answer:
[tex]\huge\boxed{y-3=\dfrac{1}{2}(x-1)}[/tex]
Step-by-step explanation:
The point-slope form of an equation of a line:
[tex]y-y_1=m(x-x_1)[/tex]
[tex]m[/tex]- slope
[tex](x_1;\ y_1)[/tex] - point on a line
We have
[tex]m=\dfrac{1}{2};\ (1;\ 3)\to x_1=1;\ y_1=3[/tex]
Substitute:
[tex]y-3=\dfrac{1}{2}(x-1)[/tex]
