Answer:
5.2,10.4,15.6,20.8,26
Step-by-step explanation:
Given that,
Common difference of an AP, d = 1.3
First term, a = 5.2
We need to find the first 5 term of the sequence.
Second term,
[tex]a_2=a+(n-1)d\\\\a_2=5.2+(2-1)(5.2)\\\\a_2=10.4[/tex]
Third term,
[tex]a_3=5.2+(3-1)(5.2)\\\\a_2=15.6[/tex]
Fouth term,
[tex]a_4=5.2+(4-1)(5.2)\\\\a_4=20.8[/tex]
Fifth term,
[tex]a_5=5.2+(5-1)(5.2)\\\\a_5=26[/tex]
The AP is : 5.2,10.4,15.6,20.8,26
