Answer:
[tex]\left(\left(\frac{2}{3}\right)^0\right)^{-3}=1[/tex]
Step-by-step explanation:
[tex]\mathrm{Apply\:exponent\:rule}:\quad \left(a^b\right)^c=a^{bc},\:\quad \:a\ge 0\\\left(\left(\frac{2}{3}\right)^0\right)^{-3}=\left(\frac{2}{3}\right)^{0\cdot \left(-3\right)}\\=\left(\frac{2}{3}\right)^0\\=1[/tex]
<3
Red
