Answer:
B
Step-by-step explanation:
Consider perfect squares on either side of 132, that is
121 < 132 < 144 , thus
[tex]\sqrt{121}[/tex] < [tex]\sqrt{132}[/tex] < [tex]\sqrt{144}[/tex] , that is
11 < [tex]\sqrt{132}[/tex] < 12 → B
its b
it didnt let me answer for some reason
