Answer:
66°
Step-by-step explanation:
[tex]\because \overrightarrow{QS} \: bisects\: \angle RQP\\\\
\therefore m\angle RQS = m\angle SQP\\\\
\therefore 2x + 10 = 3x - 18\\\\
\therefore 18 + 10 = 3x - 2x\\\\
\therefore 28 = x\\\\
\therefore x = 28\\\\
m\angle RQS = (2x + 10)\degree \\\\
m\angle RQS = (2\times 28+ 10)\degree \\\\
m\angle RQS = (56+ 10)\degree \\\\
\huge \purple {\boxed {m\angle RQS =66\degree}} \\\\
[/tex]
