If , a = 4 and b = 3
Then :-
[tex] = 6 + \frac{4}{4} + \frac{3}{3} [/tex]
[tex] = 6 + \frac{(4 \times 3)}{12} + \frac{(3 \times 4)}{12} [/tex]
[tex] = 6 + \frac{(12 + 12)}{12} [/tex]
[tex] = 6 + \frac{2}{1} [/tex]
[tex] = 6 + 2 \\ [/tex]
[tex] = 8[/tex]
[tex]∴6 + \frac{4}{4} + \frac{3}{3} =8[/tex]
