Answer:
y=2
Step-by-step explanation:
Logarithmic Equations
The following equation is given:
[tex]log_y 8+ log_y 4=5[/tex]
Recall the property:[tex]log_b x+lob_b y=log_b (x.y)[/tex]
Applying: [tex]log_y 32=5[/tex]
Now recall the definition of the log:
If:
[tex]log_b a=x[/tex]
Then
[tex]b^x=a[/tex]
The equation becomes:
[tex]y ^5=32[/tex]
But 32=2^5, so:
[tex]y ^5=2^5[/tex]
Equating the bases:
y=2
