Answer:
see below
Step-by-step explanation:
the circumference of a circle is
[tex]2\pi r[/tex]
in our problem
r=11
[tex]C=2\pi (11)\\\\=22\pi[/tex]
rounded to the nearest tenth
[tex]C\approx69.1[/tex]
the area of a circle is
[tex]\pi r^2[/tex]
so the area is
[tex]A=\pi(11)^2\\\\=121\pi[/tex]
rounded to nearest tenth
[tex]A\approx 380.1[/tex]
