Answer:
105 g O₂
Explanation:
Step 1: Define
Molar Mass O - 16.00 g/mol
Molar Mass O₂ - 2(16.00) = 32.00 g/mol
Step 2: Use Dimensional Analysis
[tex]3.28 \hspace{3} mol \hspace{3} O_2(\frac{32 \hspace{3} g \hspace{3} O_2}{1 \hspace{3} mol \hspace{3} O_2} )[/tex] = 104.96 g O₂
Step 3: Simplify
We are given 3 sig figs.
104.96 g O₂ ≈ 105 g O₂
