sarpg85 sarpg85
  • 17-10-2020
  • Mathematics
contestada

Write an equation of the line that passes through (2,−5) and is parallel to the line 2y=3x+10

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3marxz
3marxz 3marxz
  • 19-10-2020

Step-by-step explanation:

Divide two on both sides to get rid of it and the make the equation in the form y = mx + c

[tex] \frac{2}{2} y = \frac{3}{2} x + \frac{10}{2} [/tex]

y = 3/2x + 5

since both lines are parallel they must have the same gradient which is 3/2

y = 3/2x + c

All you have to do now is to replace x and y with (2, -5) to find c

x = 2

y = -5

-5 = 3/2 × 2 + c

-5 = 3 + c

c = -5-3

c = -8

[tex]y = \frac{3}{2} x - 8[/tex]

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