Answer:
Change in temperature = ΔT = 26.8°C
Explanation:
Given data:
Heat absorbed = 600 j
Mass = 25.0 g
Specific heat capacity = 0.897j /g°C
Change in temperature = ΔT= ?
Solution:
Formula:
q = mcΔT
600 j = 25.0 g ×0.897 j/g°C×ΔT
600 j = 22.425 j/°C×ΔT
ΔT = 600 j /22.425 j/°C
ΔT = 26.8°C
