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  • 16-10-2020
  • Mathematics
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Rewrite by completing the square 2x^2+7x+6=0

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unicorn3125
unicorn3125 unicorn3125
  • 18-10-2020

Answer:

[tex]2x^2+7x+6=0\\\\2(x^2+\frac72x+3)=0\\\\2[x^2+2\cdot x\cdot\frac74+(\frac74)^2-(\frac74)^2+3]=0\\\\2[x^2+2\cdot x\cdot\frac74+(\frac74)^2]-2(\frac74)^2+6=0 \\\\2(x+\frac74)^2-2\cdot\frac{49}{16}+6=0\\\\2(x+\frac74)^2-\frac{49}8+\frac{48}8=0\\\\2(x+\frac74)^2-\frac18=0[/tex]

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camellarosegarcia camellarosegarcia
  • 27-04-2021

Answer:

(x+7/4)^2=1/16

Step-by-step explanation:

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