2 consecutive odd integers : x and x + 2
x(x + 2) = 27 + 6(x + x + 2)
x^2 + 2x = 27 + 6(2x + 2)
x^2 + 2x = 27 + 12x + 12
x^2 + 2x - 12x - 12 - 27 = 0
x^2 -10x - 39 = 0
(x + 3)(x - 13) = 0
x + 3 = 0
x = -3 (extraneous solution)
x - 13 = 0
x = 13
x + 2 = 15
so ur 2 integers are 13 and 15, with 15 being the largest
