Febraden1beth Febraden1beth

20-09-2016
Mathematics

contestada

Find the exact real value of arccos(-sqrt(2)/2).

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Hussain514 Hussain514

24-09-2016

arccos(-sqrt(2)/2). range of cos − 1 ( x )=[ 0 , π ]
= arccos(0.706 )
=45 degrees
hope this helps

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wigwire wigwire

22-02-2021

Answer: -1

Step-by-step explanation: pre cal ED

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