Hehe, these are fun to do. There are two ways to do this kind of problem. You can use the pythagorean theorem or we can use the distance formula. Distance formula: [tex]d= \sqrt{(x2-x1)^2+(y2-y1)^2}[/tex]
Pythagorean Theorem: [tex]a^2+b^2=c^2[/tex] Distance formula is better if you're finding distance between two coordinates. The Pythagorean Theorem only really works for independent values. If I had 2 sides of a triangle, and I needed to find the third, I'd use this equation to find it. In this case, we'll use the distance formula.
I'll work the first one out for you: x1 y1 x2 y2 (3, 2) & (7, 4)
[tex]d= \sqrt{(7-3)^2+(4-2)^2} [/tex] v [tex]d= \sqrt{(4)^2+(2)^2}[/tex] v [tex]d= \sqrt{(16+4}[/tex] v [tex]d= \sqrt{20}[/tex]
There's your answer!
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