Answer:
[tex]d=\sqrt{106}[/tex]
[tex]d \approx 10.3[/tex]
Step-by-step explanation:
Consider the vector
[tex]\vec v = \overrightarrow{LM}[/tex]
[tex]\overrightarrow{LM}=M-L=(-2, 4)-(7-1)=(-9, 5)[/tex]
The distance is equal to the norm:
[tex]d=||\vec v || = \sqrt{(-9)^2 + 5^2}= \sqrt{81+25}= \sqrt{106}[/tex]
[tex]d \approx 10.3[/tex]
