Step-by-step explanation:
The root of an equation is when x=0.
We need to rewrite this as 3x²-4x+10=0.
The quadratic formula is
(-b+or-sqrt(b²-4ac))/2a
so 4+or-sqrt(16-120)/2a
since the sqrt can no be negative this answer will have imaginary numbers.
(4+2i sqrt(26))6 and (4-2i sqrt(26))6
simplified is
x=(2+i sqrt(26))/3 and x=(2-i sqrt(26))/3
