kaleyn42
kaleyn42 kaleyn42
  • 17-09-2020
  • Mathematics
contestada

In the figure, segment RD bisect segment DE at S. Given that DS=4x+12 and SE=8x-8, find the value of x.

In the figure segment RD bisect segment DE at S Given that DS4x12 and SE8x8 find the value of x class=

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akposevictor
akposevictor akposevictor
  • 22-09-2020

Answer:

[tex] x = 5 [/tex]

Step-by-step explanation:

DS = 4x + 12

SE = 8x - 8

Since segment RS bisects segment DE, it implies that the two segments created, segments DS and SE, are congruent. Therefore:

[tex] 4x + 12 = 8x - 8 [/tex]

Solve for x

[tex] 4x + 12 - 8x = 8x - 8 - 8x [/tex] (Subtraction property of equality)

[tex] -4x + 12 = - 8 [/tex]

[tex] -4x + 12 - 12 = - 8 - 12 [/tex] (subtraction property of equality)

[tex] -4x = - 20 [/tex]

[tex] \frac{-4x}{-4} = \frac{-20}{-4} [/tex]

[tex] x = 5 [/tex]

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