Weaklyemma Weaklyemma

17-09-2020
Mathematics

contestada

solve the following quadratic equation:
2x^2+19x+40=-2

A.x=2 or x= -9.5
B.x=-3.5 or x=-6
C.x=-2 or x=-21
D.x=6 or x=7

Respuesta :

bantawahenhse bantawahenhse

17-09-2020

Answer:

-3.5 or -6

Step-by-step explanation:

2x^2+19x+40=-2

2x^2+19x+40+2=0

2x^2+19x+42=0

2x^2+(12+7)x+42=0

2x^2+12x+7x+42=0

2x(x+6)+7(x+6)=0

(x+6)(2x+7)=0

either,

x+6=0

x=-6

or,

2x+7=0

2x=-7

x=-7/2

x=-3.5

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