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Doc Brown has calculated that his Delorean can accelerate at a rate of 2.52 m/s/s. How far away must he and Marty stand to allow the car to accelerate from rest to a speed of 39.1 m/s?

Respuesta :

Answer:

d = 303.33 m

Explanation:

Given that,

Acceleration of Doc Brown is 2.52 m/s²

The initial speed of Doc Brown is 0 as it was at rest.

Final speed of Doc Brown is 39.1 m/s

We need to find the distance between he and Marty. Let the distance is d. Using equation of motion as follows :

[tex]v^2-u^2=2ad\\\\\text{Put u = 0}\\\\d=\dfrac{v^2}{2a}\\\\d=\dfrac{(39.1)^2}{2\times 2.52}\\\\d=303.33\ m[/tex]

So, the distance between he and Marty is 303.33 m.

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