Answer: A 30.6 g sample of the compound X2O3 contains 14.4 g of oxygen atoms. What is ... To determine the identity of X we need to determine its atomic mass. We know ... ratio between the elements. 54.33 g C ×. 1 mol C. 12.01 g C. = 4.524 mol C. 9.15 g H × ... 9.08/2.270 = 4; thus, the compound's empirical formula is C2H4O. 6.
Explanation: I hope this helps ;)
