Answer:
The answer is YES
The value is [tex]S = 110 \ g/L[/tex]
Explanation:
From the question we are told that
The volume of the sample taken is v = 13.0 mL
The temperature is [tex]T = 16^oC[/tex]
The mass of the sample is [tex]m = 0.143 g[/tex]
Generally the solubility of the substance X is mathematically represented as
[tex]S = \frac{m}{V}[/tex]
=> [tex]S = \frac{0.143 }{13.0}[/tex]
=> [tex]S = 0.011 \ g/mL[/tex]
=> [tex]S = 110 \ g/L[/tex]
