Answer:
x = 3 and y = 0
Step-by-step explanation:
3y+x=3
-2y+5x=15
Isolate y in 3y + x = 3 :
[tex]y=[/tex] [tex]\frac{3-x}{3}[/tex]
Substitute [tex]y = \frac{3-x}{3}[/tex] in -2y + 5x = 15 :
[tex]-2 * \frac{3-x}{3} + 5x = 15[/tex]
Simplify the equation :
[tex]\frac{-6+17x}{3} =15[/tex]
Isolate x in [tex]\frac{-6 + 17x}{3} = 15[/tex] :
Proving x = 3
Isolate y in [tex]y = \frac{3-3}{3}[/tex] :
Proving y = 0
Your solved system of equations are x being 3, and y being 0.
