Cramberry2 Cramberry2
  • 19-08-2020
  • Physics
contestada

I have no idea of how to approach this problem

I have no idea of how to approach this problem class=

Respuesta :

CSMedrano
CSMedrano CSMedrano
  • 19-08-2020

Answer:

p=1

Explanation:

Well me know that v=m/s

and that a=m/s^2

so

[tex](m/s)^{2} = (m/s^2)(x^p)\\\\(m^2/s^2)/(m/s^2)=x^p\\\\m^2s^2/ms^2=x^p\\\\(m^2/m)(s^2/s^2)=x^p\\\\m=x^p\\\\p=1[/tex]

Note: We don't take into account 2 because it's a scalar, it doesn't have units so it doesn't add anything to the equation.

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