im pretty sure that it is
i
Answer:
Step-by-step explanation:
[tex] \huge {i}^{37} \\ \huge= {i}^{36} \times i \\ \huge = ( {i}^{2})^{18} \times i \\\huge = ( - 1) ^{18} \times i \\ \huge = 1 \times i \\ \huge = i \\ \\\huge \therefore {i}^{37} = i[/tex]
