Solution :-
First of all we have to find out the least common multiple of the given three numbers.
27 , 30 and 45
27 = 3 x 3 x 3
30 = 2 x 3 x 5
45 = 3 x 3 x 5
Form these factors we have to find the numbers which are common in all the three .
LCM = 2 x 3 x 3 x 3 x 5 = 270 .
Now 270 is completely divisible but the number which we want leaves 3 as remainder.
So adding 3 in 270 .
→ 273 is the required answer.
