Answer:
[tex]\Huge \boxed{(x^2 - 4x + 16)}[/tex]
Step-by-step explanation:
x³ + 64
64 is a perfect cube. Rewrite 64 as 4³.
x³ + 4³
Apply sum of cubes formula:
- a³ + b³ = (a + b)(a² - ab + b²)
a = x
b = 4
(x + 4)(x² - (x)(4) + 4²)
(x + 4)(x² - 4x + 16)
(x² - 4x + 16) is the other factor.
