Answer:
[tex]f(g(-6))=2\sqrt{10}[/tex]
Step-by-step explanation:
first we need to find g(-6)
[tex]g(x)= x^2\\\\g(-6)=(-6)^2\\\\g(-6)=36[/tex]
so g(-6)=36
so we need to find f(36)
[tex]f(x)=\sqrt{x+4} \\\\f(36)=\sqrt{36+4} \\\\f(36)=\sqrt{40}\\\\f(36)=\sqrt{4}* \sqrt{10} \\\\f(36)=2\sqrt{10}[/tex]
so that's answer
[tex]f(g(-6))=2\sqrt{10}[/tex]
