Answer:
Step-by-step explanation:
Hello, please consider the following.
For any x real number different from 0, we can write.
[tex]\dfrac{2y + x}{x} = 2y\\\\2y+x=2xy\\\\2xy-x=(2y-1)x=2y\\\\x=\dfrac{2y}{2y-1}[/tex]
And this is defined for 2y-1 different from 0, meaning y different from 1/2
Thank you.
