Answer:
(x+1)(x+1)^2
Step-by-step explanation:
[tex]\Huge \boxed{(x+1)^3}[/tex]
x³ + 3x² + 3x + 1
Apply cube of sum rule :
⇒ a³ + 3a²b + 3ab² + b³ = (a + b)³
(x)³ + 3(x)²(1) + 3(x)(1)² + (1)³
⇒ a = x
⇒ b = 1
(x + 1)³
