tbird1270
tbird1270 tbird1270
  • 16-08-2020
  • Mathematics
contestada

Use the graph of f(x)=x^2 to find a number δ such that ∣x^2−1∣<0.1 whenever 0<|x−1|<δ.

Use the graph of fxx2 to find a number δ such that x21lt01 whenever 0ltx1ltδ class=

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Bebong Bebong
  • 16-08-2020

Answer:

[tex]\delta=0.0333[/tex]

Step-by-step explanation:

[tex]|x^2-1}=|x-1||x+1|<0.1[/tex]

[tex]|x|-|1|<|x-1|<1[/tex]

[tex]|x|<2[/tex]

[tex]|x+1|<3[/tex]

Hence

[tex]|x-1|<\frac{0.1}{|x+1|}[/tex]

[tex]|x-1|<\frac{0.1}{3}=0.333 =\delta[/tex]

Hopefully you get what I meant!!

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