Hello, please consider the following.
[tex]{2}^{x + 2 } = 9 \times( {2}^{x} ) - 2\\\\2^x \cdot 2^2=9\cdot 2^x-2\\\\(9-4)2^x = 2\\\\2^x=\dfrac{2}{5}\\\\\text{We take the ln.}\\\\xln(2)=ln(2)-ln(5)\\\\x=\dfrac{ln(2)-ln(5)}{ln(2)}=-1.32193...[/tex]
Let me know if you need further explanation.
Thank you
