Answer:
A
Step-by-step explanation:
Given
f(x) = [tex]\frac{3+x}{x-3}[/tex]
To evaluate f(a + 2), substitute x = a + 2 into f(x)
f(a + 2) = [tex]\frac{3+a+2}{a+2-3}[/tex] = [tex]\frac{5+a}{a-1}[/tex] → A
