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20-07-2020
Mathematics

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whats the extreme value?y=3(x+5)^(2)-4

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bekkarmahdi702 bekkarmahdi702

20-07-2020

Answer:

-4

Step-by-step explanation:

y = 3(x+5)²-4
y= 3(x²+10x+25)-4
y= 3x²+30x+75-4
y= 3x²+30x+71

Derivate the function

y' = 6x+30

solve the equation y'= 0

y'= 6x+30
6x+30= 0
6x= -30
x = -5

The extrme value of y is reached in -5

y = 3(-5+5)²-4= -4

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