Answer:
C, 3.00 moles
Explanation:
First, balance the equation.
4Al + 3O2 ---> 2Al2O3
From the balanced equation, assuming Al is limiting, the mole ratio of Al:Al2O3 = 4:2 = 2:1,
meaning every 2 moles of Al used, produces 1 mole of Al2O3.
So, since 1.5 moles of Al2O3 is produced,
the no. of moles of Al used = 1.5 x2
= 3.0 moles
= C
