Answer:
0.4 ; 0.8
Step-by-step explanation:
Given that :
y varies jointly as x and z and inversely as the square of w
y ∝ xz ∝ 1/w^2
y = kxz/w^2 - - - - (1)
Given that y =3 when x=3, z=10, w=2
Inputting the values into (1)
3 = (k*3*10) / 2^2
3 = 30 × k / 4
k × 30 = 3 × 4
k × 30 = 12
k = 12/30
k = 0.4
B.) Given that ;
y=4 when x=4 z=20 w=4
Input values into (1)
y = kxz/w^2
4 = ( k * 4 * 20) / 4^2
4 = (k * 80) / 16
k * 80 = 16 * 4
k * 80 = 64
k = 64 / 80
k = 0.8
